3(2x-1)=5[3x-(2-x)]

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Solution for 3(2x-1)=5[3x-(2-x)] equation:


Simplifying
3(2x + -1) = 5[3x + -1(2 + -1x)]

Reorder the terms:
3(-1 + 2x) = 5[3x + -1(2 + -1x)]
(-1 * 3 + 2x * 3) = 5[3x + -1(2 + -1x)]
(-3 + 6x) = 5[3x + -1(2 + -1x)]
-3 + 6x = 5[3x + (2 * -1 + -1x * -1)]
-3 + 6x = 5[3x + (-2 + 1x)]

Reorder the terms:
-3 + 6x = 5[-2 + 3x + 1x]

Combine like terms: 3x + 1x = 4x
-3 + 6x = 5[-2 + 4x]
-3 + 6x = [-2 * 5 + 4x * 5]
-3 + 6x = [-10 + 20x]

Solving
-3 + 6x = -10 + 20x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-20x' to each side of the equation.
-3 + 6x + -20x = -10 + 20x + -20x

Combine like terms: 6x + -20x = -14x
-3 + -14x = -10 + 20x + -20x

Combine like terms: 20x + -20x = 0
-3 + -14x = -10 + 0
-3 + -14x = -10

Add '3' to each side of the equation.
-3 + 3 + -14x = -10 + 3

Combine like terms: -3 + 3 = 0
0 + -14x = -10 + 3
-14x = -10 + 3

Combine like terms: -10 + 3 = -7
-14x = -7

Divide each side by '-14'.
x = 0.5

Simplifying
x = 0.5

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